Wire Finder

This circuit is a simple, contactless wire / mains voltage detector. It can detect 230 V mains wiring from a distance of 10–15 cm, indicated by a red LED and a buzzing sound. You can find the circuit in Tinkercad:

👉 https://www.tinkercad.com/things/cZa2iaSgAAG-wire-tracer

The L1 coil is a self-supporting air-core coil. It can be made from a 10–12 cm long, approx. 0.5 mm diameter stiff insulated wire, loosely wound around a rod with a diameter of about 3–5 mm (e.g. a wooden skewer), which is then removed. The exact size and number of turns are not critical.

Piezo 1 is a piezo buzzer with a built-in driver circuit, meaning it will produce sound when a DC voltage is applied.

Power supply: 9V 6LR61 alkaline battery. Maximum current draw is 20 mA, and the device only consumes power when the pushbutton is held down, which conserves the battery.

Required components

NameQuantityComponent
Mini breadboard1BB-170 prototype board
T1, T2, T33Any general-purpose NPN transistor with h21e ≈ 150…250, e.g. BC237B, BC547B, BC557B
R111 MΩ resistor
R21100 kΩ resistor
R31330 Ω resistor
D115 mm red LED
PIEZO11Piezo buzzer with built-in oscillator
L11Coil antenna (see text)
S11Pushbutton
BAT119V battery clip
BAT119V battery

How it works

The wire acts as an antenna, picking up energy from the AC electric field emitted by live mains wiring. A very small base current flows into transistor T1, triggering its collector current. The induced voltage is amplified by the three cascaded transistors, producing enough current to drive the LED and buzzer.

The collector current (IC) equals the base current (IB) multiplied by the current gain: IE ≈ h21e · IB. The current gain (h21e) is a datasheet value, though it may vary even between identical transistor types. In this circuit we assume h21e ≈ 200 for each transistor. The emitter current is: IE = IC + IB,, but since IC ≫ IB, we can approximate IE ≈ h21e · IB

Because the three transistors are cascaded: T2’s base current comes from T1’s emitter; T3’s base current comes from T2’s emitter. So:

IB.T2 = IE.T1

IB.T3 = IE.T2

Which gives:

IE.T2 ≈ h21e · IB.T2 ≈ h21e · IE.T1 ≈ h21e · h21e · IB.T1

IE.T3 = h21e · IB.T3 ≈ h21e · IE.T2 ≈ h21e · h21e · h21e · IB.T1 ≈ (h21e)³ · IB.T1

If h21e = 200, then (h21e)³ = 200 · 200 · 200 = 8.000.000, meaning the three transistors together amplify the current eight million times. To fully light the LED, approx. 20 mA is needed. That requires only 2.5 pA (picoamperes) of base current at T1—just eight-millionth of 20 mA. This minuscule current can easily be picked up from the electric field around live wires.


Tip

Your home is full of electric fields from appliances and mains wiring—this is often referred to as “electrosmog.” It includes both low-frequency (from power lines and devices) and high-frequency (radio, TV, mobile phones, Wi-Fi) components.

If the circuit is too sensitive, it may detect all sorts of electric fields. In that case, it can be used as an electrosmog detector. If you want to use it as a wire finder, consider replacing one of the transistors with a lower-gain version.


Bonus tip: Finding a faulty bulb in an old-style Christmas light string

The device can also help identify a burnt-out bulb in a traditional incandescent Christmas light string (not LED). Here’s how:

  1. Plug the light string into a socket.
  2. Use the device to probe near the wire segment between the first two bulbs.
  3. The device will either buzz/light up or remain silent.
  4. Move to the next segment and repeat.
  5. Continue until you find a bulb where the device reacts on one side but not the other—that bulb is faulty!
  6. Unplug the string and replace the bad bulb.

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